Problem 16.17

16.17. a)
Again we are dealing with length contraction (expansion).
$\alpha = 9.00 \times 10^{-6} (C{}^{\circ})^{-1}$
$\Delta T = 65{}^{\circ}C$
$\Delta L = L_{0} \alpha \Delta T$
$\Delta L = .176 mm$

b)
The radius is also a length, so once again,
$\Delta L = L_{0} \alpha \Delta T$
$\Delta L = 8.78 \times 10^{-4} cm$

c)
For volume changes,
$\beta = 3\alpha$
$\Delta V = V_{0} 3\alpha \Delta T$
$V_{0} = \frac{(30)(\pi)(1.5)^{2}}{4}$
$\Delta V = .0930 cm^{3}$