Problem 16.35

16.35.
FIrst, let's find the force that the molecules exert on the wall.
$F = \frac{\Delta p}{\Delta t}$
$F = \frac{m\Delta v}{\Delta t}$
The mass of the Nitrogen hitting the wall in one second is given by
$m = (5 \times 10^{23})(4.68 \times 10^{-26} kg)$
The change in velocity is twice the initial velocity as the molecules rebound with the same velocity that they hit the wall with.
So, the force is
$F = \frac{(5 \times 10^{23})(4.68 \times 10^{-26} kg)(2)(300 m/s)}{1 sec}$
F = 14.0 N
The pressure is given from the formula
$P = \frac{F}{A}$
$P = \frac{14.0 N}{8 \times 10^{-4} m^{2}}$
$P = 1.76 \times 10^{4} Pa$