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Problem 17.47

17.47. a)
The work done during each segment is equal to the area under each part of the PV curve.
W = WDA + WAB + WBC + WCD
W = P0(V0-3V0) + 0 + 3P0(3V0-V0) + 0
W = 4P0V0



b)
Since the initial and final values of the temperature of the system are equal, then $\Delta U = 0$. It then follows that Q = W, so
Q = W = 4P0V0



c)
Since P0V0 = nRT0, then the work equals,
W = 4P0V0 = 4nRT0
W = 4(1)(8.31)(273)
$W = 9.08 \times 10^{3} J$






Jason George Zeibel
12/10/1997