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Problem 5.11

5.11. a)

The rope makes an angle of tex2html_wrap_inline362 with the x axis. Summing the forces in the y direction yields

tex2html_wrap_inline364

From which we find that the magnitude of the normal force, n, is 19.1 N. That leads us to the force of kinetic friction, which we find is

tex2html_wrap_inline370

From the x components, we find that

tex2html_wrap_inline372

or, tex2html_wrap_inline374

b)

Now, we want to find the angle at which the acceleration is zero. In the x direction,

tex2html_wrap_inline376

and the force of friction is given by

tex2html_wrap_inline378

tex2html_wrap_inline380

tex2html_wrap_inline382

So, applying the quadratic formula, we find that

tex2html_wrap_inline384

or, tex2html_wrap_inline386

The negative root to this would imply that the pulley was below the block, but we know that it is above it, so only consider the positive value. Then, to find the x distance, we take the tangent of our angle tex2html_wrap_inline388 .

tex2html_wrap_inline390

or, x = 6.10 cm



Jason George Zeibel
Thu Oct 16 01:36:21 EDT 1997