Problem 8.27

8.27.

By conservation of momentum in the $\hat{x}$ direction,

$5 m/s + 0 = (4.33 m/s)(\cos 30{}^{\circ}) + v_{2fx}$

v_2fx  =  1.25 m/s

and in the $\hat{y}$ direction,

$0 = 4.33 \sin 30{}^{\circ}+ v_{2fy}$

v_2fy  =  -2.16 m/s

$\vec{V} = 2.50 m/s$ at $\theta = - 60{}^{\circ}$.