Problem 22.5

22.5
The gravitational force is given by our old friend,
$\vec{F_{g}} = m \vec{g}$
$\vec{F_{g}} = (9.11 \times 10^{-31} kg)(9.81 m/s^{2})$ downward
$\vec{F_{g}} = 8.93 \times 10^{-30} N$ downward.
 
The electric force is given by
$\vec{F_{e}} = q \vec{E}$
$\vec{F_{e}} = (-1.6 \times 10^{-19} C)(100 N/C)$
$\vec{F_{e}} = 1.60 \times 10^{-17} N$ upward
 
The magnetic force is given by
$\vec{F_{m}} = q \vec{V} \times \vec{B}$
$\vec{F_{m}} = (-1.6 \times 10^{-19}C)(6 \times 10^{6} m/s) east \times (50 \times 10^{-6} T) north$
$\vec{F_{m}} = -4.80 \times 10^{-17} N$ up
$\vec{F_{m}} = 4.80 \times 10^{-17} N$ downward