Lift. In class we derived the velocity field for nonviscous
irrotational flow past a cylinder:
By integrating the pressure around the cylinder we were able to show that
there was no drag on the cylinder. Now suppose that there is some net
circulation
of the fluid about the cylinder (due to rotation of
the cylinder, say), which can be superimposed on the irrotational flow. The
circulating flow can be represented as a vortex at the center of the
cylinder, which has a velocity field
Therefore, our new velocity field has a radial component given by
Eq.(1), and an angular component given by the sum of
Eq.(2) and Eq. (3).
- Show that the superimposed velocity field still has a net circulation
for a path which encloses the cylinder. - Calculate the fluid velocity on the surface of the cylinder, and from
Bernoulli's Law the pressure distribution on the surface of the cylinder.
From the pressure find the lift and drag on the cylinder. You should find
that the drag is still zero while the magnitude of the lift (per unit length
of the cylinder) is
. How does the direction of lifting
force depend upon the sense of circulation of the fluid? - The conclusion here is that a nonviscous fluid can exert a lifting
force on the cylinder but not a drag force. Is this paradoxical? [Hint:
think about the work done by the lifting force.]
- Compute the cartesian components of the velocity and make a couple of
plots, using MAPLE, for suitable values of the dimensionless parameter