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Problem 5.27

5.27. a)

We know that after the block has reached terminal velocity (when it has fallen more than .5 m), that the acceleration is zero. Therefore, we can find the constant c.

a = g - c v = 0

tex2html_wrap_inline418

Also, since the styrofoam falls 1.5 m at constant speed in t = 5s, then we can find the terminal velocity, tex2html_wrap_inline424 .

tex2html_wrap_inline426

Therefore, the constant c is given by

tex2html_wrap_inline430

b)

Pluggin in zero for the velocity, or by reasoning we can see that the acceleration of the styrofoam when we just release the block at t=0 is zero.

c)

When v = .15 m/s,

tex2html_wrap_inline436 in the negative y direction.



Jason George Zeibel
Thu Oct 16 01:36:21 EDT 1997