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Ideal fluids and Euler's equation

To obtain our next equation of motion we appeal to Newton's Second Law--the mass of a fluid element times its acceleration is equal to the net force acting on that fluid element. If we take an element of unit volume, then we have

  equation214

where tex2html_wrap_inline995 is the force per unit volume on a fluid element. This force may have several contributions. The first is the ``internal'' force which is due to viscous dissipation, which we will ignore for right now. The second set are ``body forces'' which act throughout the volume of the fluid, such as the gravitational force. The third force is due to pressure gradients within the fluid. To see how this works, consider a cube of fluid, with dimensions tex2html_wrap_inline997 , tex2html_wrap_inline999 , and tex2html_wrap_inline1001 , as shown in Fig. 2.6.

  


Figure 2.6: Derivation of the force on a fluid element due to pressure gradients.

The force on the top face at position x is tex2html_wrap_inline1005 , while the force on the bottom face is tex2html_wrap_inline1007 ; subtracting, we see that the net force in the x-direction is tex2html_wrap_inline1011 , so the pressure per unit volume is tex2html_wrap_inline1013 . Repeating for the y and z directions, we find the net force per unit volume tex2html_wrap_inline1019 . Therefore, if we ignore viscosity and gravity for the moment, we have

 

Now comes the tricky part. What is the acceleration of the fluid? We want the acceleration of a particular element of the fluid; the coordinates of this fluid element change in time as the fluid flows. In a time interval tex2html_wrap_inline1021 , the x-coordinate changes by tex2html_wrap_inline1025 , the y-coordinate by tex2html_wrap_inline1029 , and the z-coordinate by tex2html_wrap_inline1033 . The velocity then becomes

  eqnarray230

To calculate the acceleration, we need to find the rate of change of the velocity:

  eqnarray239

We see that the acceleration is not simply tex2html_wrap_inline1035 . The reason for this is that even if tex2html_wrap_inline1037 , so that the velocity at a given point is not changing, that doesn't mean that a fluid element is not accelerating. A good example is circular flow in a bucket. If the flow is steady, then at a point in the bucket tex2html_wrap_inline1037 , even though a fluid element in the bucket is experiencing a centripetal acceleration. The term tex2html_wrap_inline1041 is nonlinear, and is the source of all of the difficulties in fluid mechanics. Pulling together all of the pieces, we have for our equation of motion

  equation260

This is known as Euler's equationEuler's equation. This equation, along with the equation of continuity, are the governing equations of nonviscous fluid flow.

The Euler equation can be written in a somewhat different form which is often useful for applications. We use the following identity from vector calculus:

  equation268

[see the PDR, p. 15, Eq. (12)]. Next we use tex2html_wrap_inline1043 , and the fact that the fluid is incompressible so that tex2html_wrap_inline913 is constant, to rewrite Eq. (2.20) as

  equation279


next up previous
Next: Laminar vs. turbulent flow Up: Steady flows of incompressible Previous: Steady flows of incompressible

Vittorio Celli
Mon Aug 11 22:46:35 EDT 1997